9.3 Graphics9.5 Integral Representations

§9.4 Maclaurin Series

For z\in\Complex

9.4.1\mathop{\mathrm{Ai}\/}\nolimits\!\left(z\right)=\mathop{\mathrm{Ai}\/}\nolimits\!\left(0\right)\left(1+\frac{1}{3!}z^{3}+\frac{1\cdot 4}{6!}z^{6}+\frac{1\cdot 4\cdot 7}{9!}z^{9}+\cdots\right)+{\mathop{\mathrm{Ai}\/}\nolimits^{{\prime}}}\!\left(0\right)\left(z+\frac{2}{4!}z^{4}+\frac{2\cdot 5}{7!}z^{7}+\frac{2\cdot 5\cdot 8}{10!}z^{{10}}+\cdots\right),
9.4.2{\mathop{\mathrm{Ai}\/}\nolimits^{{\prime}}}\!\left(z\right)={\mathop{\mathrm{Ai}\/}\nolimits^{{\prime}}}\!\left(0\right)\left(1+\frac{2}{3!}z^{3}+\frac{2\cdot 5}{6!}z^{6}+\frac{2\cdot 5\cdot 8}{9!}z^{9}+\cdots\right)+\mathop{\mathrm{Ai}\/}\nolimits\!\left(0\right)\left(\frac{1}{2!}z^{2}+\frac{1\cdot 4}{5!}z^{5}+\frac{1\cdot 4\cdot 7}{8!}z^{8}+\cdots\right),
9.4.3\mathop{\mathrm{Bi}\/}\nolimits\!\left(z\right)=\mathop{\mathrm{Bi}\/}\nolimits\!\left(0\right)\left(1+\frac{1}{3!}z^{3}+\frac{1\cdot 4}{6!}z^{6}+\frac{1\cdot 4\cdot 7}{9!}z^{9}+\cdots\right)+{\mathop{\mathrm{Bi}\/}\nolimits^{{\prime}}}\!\left(0\right)\left(z+\frac{2}{4!}z^{4}+\frac{2\cdot 5}{7!}z^{7}+\frac{2\cdot 5\cdot 8}{10!}z^{{10}}+\cdots\right),
9.4.4{\mathop{\mathrm{Bi}\/}\nolimits^{{\prime}}}\!\left(z\right)={\mathop{\mathrm{Bi}\/}\nolimits^{{\prime}}}\!\left(0\right)\left(1+\frac{2}{3!}z^{3}+\frac{2\cdot 5}{6!}z^{6}+\frac{2\cdot 5\cdot 8}{9!}z^{9}+\cdots\right)+\mathop{\mathrm{Bi}\/}\nolimits\!\left(0\right)\left(\frac{1}{2!}z^{2}+\frac{1\cdot 4}{5!}z^{5}+\frac{1\cdot 4\cdot 7}{8!}z^{8}+\cdots\right).